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<title>Pre-Cal 40S Wiki Solutions Manual</title>
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<description>This wiki is a collaborative solutions manual built by the student&apos;s in Mr. Kuropatwa&apos;s grade 12 precalculus math class.    Don&apos;t you just love this wiki math stuff?</description>
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  <pubDate>Wed, 17 Oct 2007 16:08:20 +0000</pubDate>
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Pre-Cal 40S Wiki Solutions Manual<br /> only.<span style="color:red;background-color:#fcc;"> Note:</span><span style="font-weight:bold;color:green;background-color:#cfc;"><br />Note:</span> All solutions have been generated by students and have not been &quot;corrected.&quot; Some of them are correct and some are not. It is up to the reader to verify the accuracy of any solution found on these pages.<br />This is a place for students to help each other learn by writing a collaborative solutions manual! This counts for marks. You must make at least two edits/contributions to the wiki. One must be a significant contribution and the other must be a constructive modification. Here is what you have to do:<br />A Significant Contribution means ...<br />]]></description>
  <pubDate>Wed, 17 Oct 2007 16:02:08 +0000</pubDate>
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  <author>email.hidden@example.com (Darren Kuropatwa)</author>
  <description><![CDATA[<h3>Darren Kuropatwa edited <a href="http://pc40s.pbwiki.com/FrontPage">FrontPage</a></h3>
<div class="diffnone">! Pre-Cal 40S Wiki Solutions Manual</div><br />
<div style="font-weight:bold;color:green;background-color:#cfc;"> This wiki is now closed. It is open for viewing only. </div><br />
<div style="font-weight:bold;color:green;background-color:#cfc;"> **Note:** All solutions have been generated by students and have not been "corrected." Some of them are correct and some are not. It is up to the reader to verify the accuracy of any solution found on these pages.</div><br />
<div class="diffnone">This is a place for students to help each other learn by writing a collaborative solutions manual! This counts for marks. You must make at least two edits/contributions to the wiki. One must be a **significant contribution** and the other must be a **constructive modification**. Here is what you have to do:</div><br />
<div class="diffnone">!!! A Significant Contribution means ...</div><br />
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  <pubDate>Thu, 04 Jan 2007 14:39:21 +0000</pubDate>
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  <title>ExponentsAndLogs</title>
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  <author>email.hidden@example.com (aldridge)</author>
  <description><![CDATA[<h3>aldridge <a href="http://pc40s.pbwiki.com/discussion.php?page=ExponentsAndLogs">commented on</a> <a href="http://pc40s.pbwiki.com/ExponentsAndLogs">ExponentsAndLogs</a></h3>
i dont know what happened to the comment i leave before but i hope this is enough for the constructive modification part cause its hard for me to explain again this stuff. sorry for not asking your permission cause its almost a few munites before the deadline.]]></description>
  <pubDate>Sun, 04 Jun 2006 23:31:16 +0000</pubDate>
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  <description><![CDATA[<h3>aldridge <a href="http://pc40s.pbwiki.com/discussion.php?page=ExponentsAndLogs">commented on</a> <a href="http://pc40s.pbwiki.com/ExponentsAndLogs">ExponentsAndLogs</a></h3>
I don't know what happened to the coment that i leave here a few seconds ago but I want to make a comment for the one who did problem 3 of 3, i cannot write everything i wrote before but what i want to say is that the question is asking for the time between after the treatment and the colony to reach 12600. i got 105.93 hours as an answer for that.]]></description>
  <pubDate>Sun, 04 Jun 2006 23:28:44 +0000</pubDate>
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  <description><![CDATA[<h3>aldridge <a href="http://pc40s.pbwiki.com/discussion.php?page=FrontPage">commented on</a> <a href="http://pc40s.pbwiki.com/FrontPage">FrontPage</a></h3>
well i'm leaving this comment for the problem 3 of 3. I think the first thing you need to do is to determine the population of the colony before Dr. Mc Coy treats the colony with an agent that slows the colony's rate growth which is after 4 hours since the beginning of the experiment (I got 2560 for that) .starting from this new colony population, you need to determine how long it will take the size of the colony to reach 12600 (thats from 2560 to 12600 because the question is asking how long after the treatment will the size reach 12600). using your formula, you can make A=12600(final amount), Ao=2560(initial amount), m=1.2(growth rate of 20% per period) and p=12(3 times the original period to reach your growth rate and this is much easier than determining the new growth rate). now the missing value is t or time. using those value in the equation, you can now get the time. In my answer, I got 105.93 hours long it took the colony to reach 12600 population after the treatment. sorry for not asking you permissi]]></description>
  <pubDate>Sun, 04 Jun 2006 23:23:59 +0000</pubDate>
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  <title>ExponentsAndLogs</title>
  <link>http://pc40s.pbwiki.com/ExponentsAndLogs</link>
  <author>email.hidden@example.com (Jacky S.)</author>
  <description><![CDATA[<h3>Jacky S. edited <a href="http://pc40s.pbwiki.com/ExponentsAndLogs">ExponentsAndLogs</a></h3>
<div class="diffnone">&lt;font color="red"&gt;x&lt;sup&gt;2&lt;/sup&gt;+8x+16=-9x&lt;/font&gt;</div><br />
<div class="diffnone">-bring the -9x over to the other side</div><br />
&lt;font<span style="font-weight:bold;color:green;background-color:#cfc;"> color</span>="red"&gt;0=x&lt;sup&gt;2&lt;/sup&gt;+17x+16<br />
<div class="diffnone">0=(x+16)(x+1)&lt;/font&gt;</div><br />
&lt;font<span style="font-weight:bold;color:green;background-color:#cfc;"> color</span>="red"&gt; - X is rejected for both of them because in the original equation,  2log&lt;sub&gt;3&lt;/sub&gt;(x+4) - log&lt;sub&gt;3&lt;/sub&gt;(-x) = 2, it is negative&lt;/font&gt;<br />
<div class="diffnone">Good try both of the previous problem solvers. I think i got the solution.</div><br />
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  <pubDate>Sun, 04 Jun 2006 23:08:42 +0000</pubDate>
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  <title>ExponentsAndLogs</title>
  <link>http://pc40s.pbwiki.com/ExponentsAndLogs</link>
  <author>email.hidden@example.com (Jacky S.)</author>
  <description><![CDATA[<h3>Jacky S. edited <a href="http://pc40s.pbwiki.com/ExponentsAndLogs">ExponentsAndLogs</a></h3>
<div class="diffnone">-Since 3 is the base, you would take 2 as the exponent</div><br />
<div class="diffnone">&lt;font color="red"&gt;x&lt;sup&gt;2&lt;/sup&gt;+8x+16/-x=3&lt;sup&gt;2&lt;/sup&gt;</div><br />
<span style="color:red;background-color:#fcc;">&lt;font color="red"&gt;</span>x&lt;sup&gt;2&lt;/sup&gt;+8x+16/-x=9<span style="font-weight:bold;color:green;background-color:#cfc;">&lt;/font&gt;</span><br />
<div class="diffnone">-cancel the denominator, by multiplying -x by both sides</div><br />
<span style="color:red;background-color:#fcc;">x&lt;sup&gt;2&lt;/sup&gt;+8x+16=-9x</span><br />
<span style="font-weight:bold;color:green;background-color:#cfc;">&lt;font color="red"&gt;x&lt;sup&gt;2&lt;/sup&gt;+8x+16=-9x&lt;/font&gt;</span><br />
<div class="diffnone">-bring the -9x over to the other side</div><br />
<div class="diffnone">&lt;font="red"&gt;0=x&lt;sup&gt;2&lt;/sup&gt;+17x+16</div><br />
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  <pubDate>Sun, 04 Jun 2006 23:07:25 +0000</pubDate>
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  <title>ExponentsAndLogs</title>
  <link>http://pc40s.pbwiki.com/ExponentsAndLogs</link>
  <author>email.hidden@example.com (Jacky S.)</author>
  <description><![CDATA[<h3>Jacky S. edited <a href="http://pc40s.pbwiki.com/ExponentsAndLogs">ExponentsAndLogs</a></h3>
<div class="diffnone">&lt;font color="red"&gt;log&lt;sub&gt;3&lt;/sub&gt;((x+4)&lt;sup&gt;2&lt;/sup&gt;)/-x=2&lt;/font&gt;</div><br />
<div class="diffnone">-Expand the binomial</div><br />
&lt;font color="red"&gt;log&lt;sub&gt;3&lt;/sub&gt;<span style="color:red;background-color:#fcc;">&lt;</span><span style="font-weight:bold;color:green;background-color:#cfc;">(</span>x&lt;sup&gt;2&lt;/sup&gt;+8x+16<span style="color:red;background-color:#fcc;">&gt;</span><span style="font-weight:bold;color:green;background-color:#cfc;">)</span>/-x=2<span style="font-weight:bold;color:green;background-color:#cfc;">&lt;/font&gt;</span><br />
<div class="diffnone">-Since 3 is the base, you would take 2 as the exponent</div><br />
<div class="diffnone">&lt;font color="red"&gt;x&lt;sup&gt;2&lt;/sup&gt;+8x+16/-x=3&lt;sup&gt;2&lt;/sup&gt;</div><br />
<div class="diffnone">-cancel the denominator, by multiplying -x by both sides</div><br />
<div class="diffnone">x&lt;sup&gt;2&lt;/sup&gt;+8x+16=-9x</div><br />
<span style="font-weight:bold;color:green;background-color:#cfc;">0=x</span>&lt;<span style="color:red;background-color:#fcc;">font="red"</span><span style="font-weight:bold;color:green;background-color:#cfc;">sup</span>&gt;<span style="color:red;background-color:#fcc;">-bring the -9x over to the other side</span><span style="font-weight:bold;color:green;background-color:#cfc;">2&lt;/sup&gt;+17x+16</span><br />
<div class="diffad]]></description>
  <pubDate>Sun, 04 Jun 2006 23:04:36 +0000</pubDate>
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  <title>ExponentsAndLogs</title>
  <link>http://pc40s.pbwiki.com/ExponentsAndLogs</link>
  <author>email.hidden@example.com (Jacky S.)</author>
  <description><![CDATA[<h3>Jacky S. edited <a href="http://pc40s.pbwiki.com/ExponentsAndLogs">ExponentsAndLogs</a></h3>
<div class="diffnone">&lt;font color="red"&gt;x&lt;sup&gt;2&lt;/sup&gt;+8x+16/-x=9</div><br />
<div class="diffnone">-cancel the denominator, by multiplying -x by both sides</div><br />
<div style="font-weight:bold;color:green;background-color:#cfc;">x&lt;sup&gt;2&lt;/sup&gt;+8x+16=-9x</div><br />
<div style="font-weight:bold;color:green;background-color:#cfc;">&lt;font="red"&gt;-bring the -9x over to the other side</div><br />
<div style="font-weight:bold;color:green;background-color:#cfc;">0=x&lt;sup&gt;2&lt;/sup&gt;+17x+16</div><br />
<div style="font-weight:bold;color:green;background-color:#cfc;">0=(x+16)(x+1)&lt;/font&gt;</div><br />
<div style="font-weight:bold;color:green;background-color:#cfc;">&lt;font="red"&gt; - X is rejected for both of them because in the original equation,  2log&lt;sub&gt;3&lt;/sub&gt;(x+4) - log&lt;sub&gt;3&lt;/sub&gt;(-x) = 2, it is negative&lt;/font&gt;</div><br />
<div class="diffnone">Good try both of the previous problem solvers. I think i got the solution.</div><br />
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  <pubDate>Sun, 04 Jun 2006 23:02:22 +0000</pubDate>
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  <author>email.hidden@example.com (michael d)</author>
  <description><![CDATA[<h3>michael d edited <a href="http://pc40s.pbwiki.com/ExponentsAndLogs">ExponentsAndLogs</a></h3>
<div class="diffnone">-cancel the denominator, by multiplying -x by both sides</div><br />
<div style="font-weight:bold;color:green;background-color:#cfc;">Good try both of the previous problem solvers. I think i got the solution.</div><br />
<div style="font-weight:bold;color:green;background-color:#cfc;">2log&lt;sub&gt;3&lt;/sub&gt;(x+4)- log&lt;sub&gt;3&lt;/sub&gt;(-x)= 2</div><br />
<div style="font-weight:bold;color:green;background-color:#cfc;">expand the equation:</div><br />
<div style="font-weight:bold;color:green;background-color:#cfc;">2log&lt;sub&gt;3&lt;/sub&gt;x + 2log&lt;sub&gt;3&lt;/sub&gt;4 - log&lt;sub&gt;3&lt;/sub&gt;(-x)= 2</div><br />
<div style="font-weight:bold;color:green;background-color:#cfc;">move the x terms to one side:</div><br />
<div style="font-weight:bold;color:green;background-color:#cfc;">2log&lt;sub&gt;3&lt;/sub&gt;x - log&lt;sub&gt;3&lt;/sub&gt;(-x) = 2 - log&lt;sub&gt;3&lt;/sub&gt;4</div><br />
<div style="font-weight:bold;color:green;background-color:#cfc;">factor out x:</div><br />
<div style="font-weight:bold;color:green;background-color:#cfc;">x(2log&lt;sub&gt;3&lt;/sub&gt;1 - log&lt;sub&gt;3&lt;/sub&gt;(-1)) = 2 - log&lt;sub&gt;3&lt;/sub&gt;</div><br />
<div style="font-weight:bold;color:green;background-color:#cfc;">By looking at the equation now, you can notice that there is a log&lt;sub&gt;3&lt;/sub&gt;(-1). We know that there is no such solution. Since we know that the expression is false, there is no w</div>]]></description>
  <pubDate>Sun, 04 Jun 2006 23:00:35 +0000</pubDate>
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<div class="diffnone">&lt;img src=/f/untitled.bmp width=70% height=70%&gt;</div><br />
<span style="color:red;background-color:#fcc;">&lt;img src=http://pc40s.pbwiki.com/upload.php?pp=5&setPerPage=10&gt;</span><br />
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  <pubDate>Sun, 04 Jun 2006 22:49:27 +0000</pubDate>
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<div class="diffnone">x = 0.282</div><br />
&lt;img src=<span style="color:red;background-color:#fcc;">http://pc40s.pbwiki.com</span>/f/<span style="font-weight:bold;color:green;background-color:#cfc;">untitled.bmp </span>wi<span style="color:red;background-color:#fcc;">kicon.JPG</span><span style="font-weight:bold;color:green;background-color:#cfc;">dth=70% height=70%</span>&gt;<br />
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[Exp<span style="font-weight:bold;color:green;background-color:#cfc;">onentsAndLogs] [Exp</span>andLogs|Learning Objectives]<br />
<div class="diffnone">! Problem 1 of 3</div><br />
<div class="diffnone">x = 0.282</div><br />
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